Base | Representation |
---|---|
bin | 111100001010000101101… |
… | …000000110000101101011 |
3 | 112122012120121010022000021 |
4 | 330022011220012011223 |
5 | 1020212413101403204 |
6 | 12443044504021311 |
7 | 604446245531131 |
oct | 74120550060553 |
9 | 15565517108007 |
10 | 4134000419179 |
11 | 1354246510954 |
12 | 569244461837 |
13 | 23cab070a6b7 |
14 | 10412dc2b751 |
15 | 72805128154 |
hex | 3c285a0616b |
4134000419179 has 2 divisors, whose sum is σ = 4134000419180. Its totient is φ = 4134000419178.
The previous prime is 4134000419167. The next prime is 4134000419191. The reversal of 4134000419179 is 9719140004314.
4134000419179 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a balanced prime because it is at equal distance from previous prime (4134000419167) and next prime (4134000419191).
It is a cyclic number.
It is not a de Polignac number, because 4134000419179 - 213 = 4134000410987 is a prime.
It is a super-2 number, since 2×41340004191792 (a number of 26 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (4134000449179) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2067000209589 + 2067000209590.
It is an arithmetic number, because the mean of its divisors is an integer number (2067000209590).
Almost surely, 24134000419179 is an apocalyptic number.
4134000419179 is a deficient number, since it is larger than the sum of its proper divisors (1).
4134000419179 is an equidigital number, since it uses as much as digits as its factorization.
4134000419179 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 108864, while the sum is 43.
The spelling of 4134000419179 in words is "four trillion, one hundred thirty-four billion, four hundred nineteen thousand, one hundred seventy-nine".
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