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41340114121 is a prime number
BaseRepresentation
bin100110100000000100…
…000001010011001001
310221201001201101110211
4212200010001103021
51134131032122441
630554050041121
72662306113025
oct464004012311
9127631641424
1041340114121
1116594464679
1280188791a1
133b8a8c3cb7
142002571385
15111e49ca81
hex9a01014c9

41340114121 has 2 divisors, whose sum is σ = 41340114122. Its totient is φ = 41340114120.

The previous prime is 41340114103. The next prime is 41340114131. The reversal of 41340114121 is 12141104314.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 36956217600 + 4383896521 = 192240^2 + 66211^2 .

It is a cyclic number.

It is not a de Polignac number, because 41340114121 - 217 = 41339983049 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 41340114092 and 41340114101.

It is not a weakly prime, because it can be changed into another prime (41340114131) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20670057060 + 20670057061.

It is an arithmetic number, because the mean of its divisors is an integer number (20670057061).

Almost surely, 241340114121 is an apocalyptic number.

It is an amenable number.

41340114121 is a deficient number, since it is larger than the sum of its proper divisors (1).

41340114121 is an equidigital number, since it uses as much as digits as its factorization.

41340114121 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 384, while the sum is 22.

Adding to 41340114121 its reverse (12141104314), we get a palindrome (53481218435).

The spelling of 41340114121 in words is "forty-one billion, three hundred forty million, one hundred fourteen thousand, one hundred twenty-one".