Base | Representation |
---|---|
bin | 1100000010000001011… |
… | …00011001100001101011 |
3 | 1110112001201020202112222 |
4 | 12001000230121201223 |
5 | 23233121433204011 |
6 | 513525300424255 |
7 | 41603331033215 |
oct | 6010054314153 |
9 | 1415051222488 |
10 | 413402241131 |
11 | 14a360873540 |
12 | 681536a808b |
13 | 2cca3157739 |
14 | 1601a1175b5 |
15 | ab48302ddb |
hex | 6040b1986b |
413402241131 has 32 divisors (see below), whose sum is σ = 464425581312. Its totient is φ = 364720000000.
The previous prime is 413402241103. The next prime is 413402241151. The reversal of 413402241131 is 131142204314.
It is a cyclic number.
It is not a de Polignac number, because 413402241131 - 210 = 413402240107 is a prime.
It is a super-2 number, since 2×4134022411312 (a number of 24 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 413402241131.
It is not an unprimeable number, because it can be changed into a prime (413402241151) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 109916291 + ... + 109920051.
It is an arithmetic number, because the mean of its divisors is an integer number (14513299416).
Almost surely, 2413402241131 is an apocalyptic number.
413402241131 is a gapful number since it is divisible by the number (41) formed by its first and last digit.
413402241131 is a deficient number, since it is larger than the sum of its proper divisors (51023340181).
413402241131 is a wasteful number, since it uses less digits than its factorization.
413402241131 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5035.
The product of its (nonzero) digits is 2304, while the sum is 26.
Adding to 413402241131 its reverse (131142204314), we get a palindrome (544544445445).
The spelling of 413402241131 in words is "four hundred thirteen billion, four hundred two million, two hundred forty-one thousand, one hundred thirty-one".
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