413402403433 has 4 divisors (see below), whose sum is σ = 413421083460. Its totient is φ = 413383723408.

The previous prime is 413402403353. The next prime is 413402403499. The reversal of 413402403433 is 334304204314.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 334304204314 = 2 ⋅167152102157.

It can be written as a sum of positive squares in 2 ways, for example, as 353469488089 + 59932915344 = 594533^2 + 244812^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-413402403433 is a prime.

It is a super-3 number, since 3×413402403433³ (a number of 36 digits) contains 333 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 413402403395 and 413402403404.

It is not an unprimeable number, because it can be changed into a prime (413402403233) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9306778 + ... + 9351091.

It is an arithmetic number, because the mean of its divisors is an integer number (103355270865).

Almost surely, 2^413402403433 is an apocalyptic number.

It is an amenable number.

413402403433 is a deficient number, since it is larger than the sum of its proper divisors (18680027).

413402403433 is a wasteful number, since it uses less digits than its factorization.

413402403433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 18680026.

The product of its (nonzero) digits is 41472, while the sum is 31.

Adding to 413402403433 its reverse (334304204314), we get a palindrome (747706607747).

The spelling of 413402403433 in words is "four hundred thirteen billion, four hundred two million, four hundred three thousand, four hundred thirty-three".