Base | Representation |
---|---|
bin | 1100000010000001100… |
… | …11000111000011100001 |
3 | 1110112001211120010221002 |
4 | 12001000303013003201 |
5 | 23233122411003411 |
6 | 513525402241345 |
7 | 41603352011423 |
oct | 6010063070341 |
9 | 1415054503832 |
10 | 413404000481 |
11 | 14a36186534a |
12 | 681541b6255 |
13 | 2cca3622484 |
14 | 1601a454813 |
15 | ab4854e33b |
hex | 6040cc70e1 |
413404000481 has 2 divisors, whose sum is σ = 413404000482. Its totient is φ = 413404000480.
The previous prime is 413404000397. The next prime is 413404000507. The reversal of 413404000481 is 184000404314.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 387798880225 + 25605120256 = 622735^2 + 160016^2 .
It is a cyclic number.
It is not a de Polignac number, because 413404000481 - 222 = 413399806177 is a prime.
It is a super-2 number, since 2×4134040004812 (a number of 24 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (413404000981) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 206702000240 + 206702000241.
It is an arithmetic number, because the mean of its divisors is an integer number (206702000241).
Almost surely, 2413404000481 is an apocalyptic number.
It is an amenable number.
413404000481 is a deficient number, since it is larger than the sum of its proper divisors (1).
413404000481 is an equidigital number, since it uses as much as digits as its factorization.
413404000481 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6144, while the sum is 29.
Adding to 413404000481 its reverse (184000404314), we get a palindrome (597404404795).
The spelling of 413404000481 in words is "four hundred thirteen billion, four hundred four million, four hundred eighty-one", and thus it is an aban number.
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