Base | Representation |
---|---|
bin | 101110111111111010011100… |
… | …0010000111101101100101011 |
3 | 2000012202002002121020212201112 |
4 | 1131333310320100331230223 |
5 | 413141204233331104003 |
6 | 4023123212425540535 |
7 | 153035325121305611 |
oct | 13577647020755453 |
9 | 2005662077225645 |
10 | 413404431113003 |
11 | 10a7a591aa28550 |
12 | 3a44866b64474b |
13 | 14989b4187bc55 |
14 | 7412c4a1296b1 |
15 | 32bd8e81e13d8 |
hex | 177fd3843db2b |
413404431113003 has 8 divisors (see below), whose sum is σ = 452922217156656. Its totient is φ = 374209239241600.
The previous prime is 413404431112999. The next prime is 413404431113207. The reversal of 413404431113003 is 300311134404314.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 413404431113003 - 22 = 413404431112999 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (413404431113603) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 80648540378 + ... + 80648545503.
It is an arithmetic number, because the mean of its divisors is an integer number (56615277144582).
Almost surely, 2413404431113003 is an apocalyptic number.
413404431113003 is a deficient number, since it is larger than the sum of its proper divisors (39517786043653).
413404431113003 is a wasteful number, since it uses less digits than its factorization.
413404431113003 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 161297086125.
The product of its (nonzero) digits is 20736, while the sum is 32.
Adding to 413404431113003 its reverse (300311134404314), we get a palindrome (713715565517317).
The spelling of 413404431113003 in words is "four hundred thirteen trillion, four hundred four billion, four hundred thirty-one million, one hundred thirteen thousand, three".
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