Base | Representation |
---|---|
bin | 1111011001101001… |
… | …0101110111010001 |
3 | 101200010001001122212 |
4 | 3312122111313101 |
5 | 31431312203213 |
6 | 1522120041505 |
7 | 204306162641 |
oct | 36632256721 |
9 | 11603031585 |
10 | 4134100433 |
11 | 1831656931 |
12 | 974603295 |
13 | 50b644698 |
14 | 2b30a0521 |
15 | 192e139a8 |
hex | f6695dd1 |
4134100433 has 2 divisors, whose sum is σ = 4134100434. Its totient is φ = 4134100432.
The previous prime is 4134100417. The next prime is 4134100459. The reversal of 4134100433 is 3340014314.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 4107143569 + 26956864 = 64087^2 + 5192^2 .
It is a cyclic number.
It is not a de Polignac number, because 4134100433 - 24 = 4134100417 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 4134100399 and 4134100408.
It is not a weakly prime, because it can be changed into another prime (4134105433) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2067050216 + 2067050217.
It is an arithmetic number, because the mean of its divisors is an integer number (2067050217).
Almost surely, 24134100433 is an apocalyptic number.
It is an amenable number.
4134100433 is a deficient number, since it is larger than the sum of its proper divisors (1).
4134100433 is an equidigital number, since it uses as much as digits as its factorization.
4134100433 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1728, while the sum is 23.
The square root of 4134100433 is about 64296.9706362594. The cubic root of 4134100433 is about 1604.9456907184.
Adding to 4134100433 its reverse (3340014314), we get a palindrome (7474114747).
The spelling of 4134100433 in words is "four billion, one hundred thirty-four million, one hundred thousand, four hundred thirty-three".
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