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4134113042233 is a prime number
BaseRepresentation
bin111100001010001100010…
…101101101111100111001
3112122012212110001010210111
4330022030111231330321
51020213130414322413
612443104005544321
7604452114026206
oct74121425557471
915565773033714
104134113042233
1113542a4044259
125692761150a1
1323cacab50965
14104140b86cad
157280ee72d3d
hex3c28c56df39

4134113042233 has 2 divisors, whose sum is σ = 4134113042234. Its totient is φ = 4134113042232.

The previous prime is 4134113042209. The next prime is 4134113042237. The reversal of 4134113042233 is 3322403114314.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3085039319184 + 1049073723049 = 1756428^2 + 1024243^2 .

It is a cyclic number.

It is not a de Polignac number, because 4134113042233 - 225 = 4134079487801 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 4134113042195 and 4134113042204.

It is not a weakly prime, because it can be changed into another prime (4134113042237) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2067056521116 + 2067056521117.

It is an arithmetic number, because the mean of its divisors is an integer number (2067056521117).

Almost surely, 24134113042233 is an apocalyptic number.

It is an amenable number.

4134113042233 is a deficient number, since it is larger than the sum of its proper divisors (1).

4134113042233 is an equidigital number, since it uses as much as digits as its factorization.

4134113042233 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 20736, while the sum is 31.

Adding to 4134113042233 its reverse (3322403114314), we get a palindrome (7456516156547).

The spelling of 4134113042233 in words is "four trillion, one hundred thirty-four billion, one hundred thirteen million, forty-two thousand, two hundred thirty-three".