Base | Representation |
---|---|
bin | 111100001010011010000… |
… | …011110101001100100101 |
3 | 112122020110111012010000010 |
4 | 330022122003311030211 |
5 | 1020214113331444331 |
6 | 12443142511440433 |
7 | 604460610442215 |
oct | 74123203651445 |
9 | 15566414163003 |
10 | 4134343234341 |
11 | 1354401a78a71 |
12 | 56931b226119 |
13 | 23cb367494c8 |
14 | 104163588245 |
15 | 72825292e46 |
hex | 3c29a0f5325 |
4134343234341 has 16 divisors (see below), whose sum is σ = 5757541042176. Its totient is φ = 2633912596656.
The previous prime is 4134343234337. The next prime is 4134343234361. The reversal of 4134343234341 is 1434323434314.
It is not a de Polignac number, because 4134343234341 - 22 = 4134343234337 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 4134343234341.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (4134343234361) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 28110105 + ... + 28256798.
It is an arithmetic number, because the mean of its divisors is an integer number (359846315136).
Almost surely, 24134343234341 is an apocalyptic number.
It is an amenable number.
4134343234341 is a deficient number, since it is larger than the sum of its proper divisors (1623197807835).
4134343234341 is a wasteful number, since it uses less digits than its factorization.
4134343234341 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 56367992.
The product of its digits is 497664, while the sum is 39.
Adding to 4134343234341 its reverse (1434323434314), we get a palindrome (5568666668655).
The spelling of 4134343234341 in words is "four trillion, one hundred thirty-four billion, three hundred forty-three million, two hundred thirty-four thousand, three hundred forty-one".
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