4134543020129 has 2 divisors, whose sum is σ = 4134543020130. Its totient is φ = 4134543020128.

The previous prime is 4134543020123. The next prime is 4134543020131. The reversal of 4134543020129 is 9210203454314.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2578593640000 + 1555949380129 = 1605800^2 + 1247377^2 .

It is a cyclic number.

It is not a de Polignac number, because 4134543020129 - 2¹² = 4134543016033 is a prime.

Together with 4134543020131, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 4134543020092 and 4134543020101.

It is not a weakly prime, because it can be changed into another prime (4134543020123) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2067271510064 + 2067271510065.

It is an arithmetic number, because the mean of its divisors is an integer number (2067271510065).

Almost surely, 2^{4134543020129} is an apocalyptic number.

It is an amenable number.

4134543020129 is a deficient number, since it is larger than the sum of its proper divisors (1).

4134543020129 is an equidigital number, since it uses as much as digits as its factorization.

4134543020129 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 103680, while the sum is 38.

The spelling of 4134543020129 in words is "four trillion, one hundred thirty-four billion, five hundred forty-three million, twenty thousand, one hundred twenty-nine".