Base | Representation |
---|---|
bin | 10010110011011011011000… |
… | …01100010100011010110011 |
3 | 12102101222012100000110002021 |
4 | 21121231230030110122303 |
5 | 20404432201110433113 |
6 | 223535403201332311 |
7 | 11465254204054321 |
oct | 1131555414243263 |
9 | 172358170013067 |
10 | 41349465327283 |
11 | 121a2234220833 |
12 | 4779978337097 |
13 | 1a0c312729a19 |
14 | a2d479374d11 |
15 | 4ba8db5c048d |
hex | 259b6c3146b3 |
41349465327283 has 2 divisors, whose sum is σ = 41349465327284. Its totient is φ = 41349465327282.
The previous prime is 41349465327253. The next prime is 41349465327307. The reversal of 41349465327283 is 38272356494314.
41349465327283 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 41349465327283 - 225 = 41349431772851 is a prime.
It is not a weakly prime, because it can be changed into another prime (41349465327253) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20674732663641 + 20674732663642.
It is an arithmetic number, because the mean of its divisors is an integer number (20674732663642).
Almost surely, 241349465327283 is an apocalyptic number.
41349465327283 is a deficient number, since it is larger than the sum of its proper divisors (1).
41349465327283 is an equidigital number, since it uses as much as digits as its factorization.
41349465327283 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 104509440, while the sum is 61.
The spelling of 41349465327283 in words is "forty-one trillion, three hundred forty-nine billion, four hundred sixty-five million, three hundred twenty-seven thousand, two hundred eighty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.080 sec. • engine limits •