Base | Representation |
---|---|
bin | 100110100000101001… |
… | …110111010011011011 |
3 | 10221201202101101212212 |
4 | 212200221313103123 |
5 | 1134141102102101 |
6 | 30555042425335 |
7 | 2662456331612 |
oct | 464051672333 |
9 | 127652341785 |
10 | 41350034651 |
11 | 1659a020062 |
12 | 802006224b |
13 | 3b8c988633 |
14 | 20039d4879 |
15 | 11202ac1bb |
hex | 9a0a774db |
41350034651 has 2 divisors, whose sum is σ = 41350034652. Its totient is φ = 41350034650.
The previous prime is 41350034633. The next prime is 41350034653. The reversal of 41350034651 is 15643005314.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-41350034651 is a prime.
Together with 41350034653, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (41350034653) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20675017325 + 20675017326.
It is an arithmetic number, because the mean of its divisors is an integer number (20675017326).
Almost surely, 241350034651 is an apocalyptic number.
41350034651 is a deficient number, since it is larger than the sum of its proper divisors (1).
41350034651 is an equidigital number, since it uses as much as digits as its factorization.
41350034651 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 21600, while the sum is 32.
Adding to 41350034651 its reverse (15643005314), we get a palindrome (56993039965).
The spelling of 41350034651 in words is "forty-one billion, three hundred fifty million, thirty-four thousand, six hundred fifty-one".
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