413543403113 has 4 divisors (see below), whose sum is σ = 414053321808. Its totient is φ = 413033484420.

The previous prime is 413543403067. The next prime is 413543403127. The reversal of 413543403113 is 311304345314.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 311304345314 = 2 ⋅155652172657.

It is a cyclic number.

It is not a de Polignac number, because 413543403113 - 2²² = 413539208809 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 413543403113.

It is not an unprimeable number, because it can be changed into a prime (413543403313) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 254958131 + ... + 254959752.

It is an arithmetic number, because the mean of its divisors is an integer number (103513330452).

Almost surely, 2^413543403113 is an apocalyptic number.

It is an amenable number.

413543403113 is a deficient number, since it is larger than the sum of its proper divisors (509918695).

413543403113 is an equidigital number, since it uses as much as digits as its factorization.

413543403113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 509918694.

The product of its (nonzero) digits is 25920, while the sum is 32.

Adding to 413543403113 its reverse (311304345314), we get a palindrome (724847748427).

The spelling of 413543403113 in words is "four hundred thirteen billion, five hundred forty-three million, four hundred three thousand, one hundred thirteen".