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41361065033047 is a prime number
BaseRepresentation
bin10010110011110000111111…
…00101101011110101010111
312102110002010201220112222021
421121320133211223311113
520410124430122024142
6223545002211314011
711466144514662424
oct1131703745536527
9172402121815867
1041361065033047
11121a7146a26421
124780074bab907
131a10440979046
14a2dc59b52d4b
154bad69b20267
hex259e1f96bd57

41361065033047 has 2 divisors, whose sum is σ = 41361065033048. Its totient is φ = 41361065033046.

The previous prime is 41361065032949. The next prime is 41361065033059. The reversal of 41361065033047 is 74033056016314.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 41361065033047 - 27 = 41361065032919 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 41361065032994 and 41361065033012.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (41361065733047) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20680532516523 + 20680532516524.

It is an arithmetic number, because the mean of its divisors is an integer number (20680532516524).

Almost surely, 241361065033047 is an apocalyptic number.

41361065033047 is a deficient number, since it is larger than the sum of its proper divisors (1).

41361065033047 is an equidigital number, since it uses as much as digits as its factorization.

41361065033047 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 544320, while the sum is 43.

The spelling of 41361065033047 in words is "forty-one trillion, three hundred sixty-one billion, sixty-five million, thirty-three thousand, forty-seven".