Base | Representation |
---|---|
bin | 100110100001010101… |
… | …011011110000000011 |
3 | 10221202112212200012122 |
4 | 212201111123300003 |
5 | 1134202013044011 |
6 | 31000131314455 |
7 | 2662655401442 |
oct | 464125336003 |
9 | 127675780178 |
10 | 41361456131 |
11 | 165a55111a6 |
12 | 8023a4ba2b |
13 | 3b921571c8 |
14 | 2005328d59 |
15 | 11212b63db |
hex | 9a155bc03 |
41361456131 has 2 divisors, whose sum is σ = 41361456132. Its totient is φ = 41361456130.
The previous prime is 41361456109. The next prime is 41361456133. The reversal of 41361456131 is 13165416314.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 41361456131 - 230 = 40287714307 is a prime.
It is a super-2 number, since 2×413614561312 (a number of 22 digits) contains 22 as substring.
Together with 41361456133, it forms a pair of twin primes.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 41361456091 and 41361456100.
It is not a weakly prime, because it can be changed into another prime (41361456133) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20680728065 + 20680728066.
It is an arithmetic number, because the mean of its divisors is an integer number (20680728066).
Almost surely, 241361456131 is an apocalyptic number.
41361456131 is a deficient number, since it is larger than the sum of its proper divisors (1).
41361456131 is an equidigital number, since it uses as much as digits as its factorization.
41361456131 is an evil number, because the sum of its binary digits is even.
The product of its digits is 25920, while the sum is 35.
The spelling of 41361456131 in words is "forty-one billion, three hundred sixty-one million, four hundred fifty-six thousand, one hundred thirty-one".
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