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414001204022113 is a prime number
BaseRepresentation
bin101111000100010000010101…
…0101100111100101101100001
32000021212010110201202201201221
41132020200222230330231201
5413230443431212201423
64024301305540255041
7153126412530322441
oct13610405254745541
92007763421681657
10414001204022113
1110aa05a19754984
123a5242596a1481
1314a011b8a73b06
147433a9d972121
1532ce1c4aade5d
hex178882ab3cb61

414001204022113 has 2 divisors, whose sum is σ = 414001204022114. Its totient is φ = 414001204022112.

The previous prime is 414001204022071. The next prime is 414001204022261. The reversal of 414001204022113 is 311220402100414.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 403022166969744 + 10979037052369 = 20075412^2 + 3313463^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-414001204022113 is a prime.

It is not a weakly prime, because it can be changed into another prime (414031204022113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 207000602011056 + 207000602011057.

It is an arithmetic number, because the mean of its divisors is an integer number (207000602011057).

Almost surely, 2414001204022113 is an apocalyptic number.

It is an amenable number.

414001204022113 is a deficient number, since it is larger than the sum of its proper divisors (1).

414001204022113 is an equidigital number, since it uses as much as digits as its factorization.

414001204022113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1536, while the sum is 25.

Adding to 414001204022113 its reverse (311220402100414), we get a palindrome (725221606122527).

The spelling of 414001204022113 in words is "four hundred fourteen trillion, one billion, two hundred four million, twenty-two thousand, one hundred thirteen".