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414053425123133 is a prime number
BaseRepresentation
bin101111000100101000101001…
…1010100101000111100111101
32000022001010021002222112011112
41132021101103110220330331
5413232322403312420013
64024341303443531405
7153133241602340405
oct13611212324507475
92008033232875145
10414053425123133
1110aa2608714a004
123a5323b2389b65
1314a060bba227a3
147436415273805
1532d072e43cba8
hex1789453528f3d

414053425123133 has 2 divisors, whose sum is σ = 414053425123134. Its totient is φ = 414053425123132.

The previous prime is 414053425123127. The next prime is 414053425123183. The reversal of 414053425123133 is 331321524350414.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 318002978039044 + 96050447084089 = 17832638^2 + 9800533^2 .

It is a cyclic number.

It is not a de Polignac number, because 414053425123133 - 214 = 414053425106749 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (414053425123183) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 207026712561566 + 207026712561567.

It is an arithmetic number, because the mean of its divisors is an integer number (207026712561567).

Almost surely, 2414053425123133 is an apocalyptic number.

It is an amenable number.

414053425123133 is a deficient number, since it is larger than the sum of its proper divisors (1).

414053425123133 is an equidigital number, since it uses as much as digits as its factorization.

414053425123133 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 518400, while the sum is 41.

Adding to 414053425123133 its reverse (331321524350414), we get a palindrome (745374949473547).

The spelling of 414053425123133 in words is "four hundred fourteen trillion, fifty-three billion, four hundred twenty-five million, one hundred twenty-three thousand, one hundred thirty-three".