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414102041 is a prime number
BaseRepresentation
bin11000101011101…
…011001000011001
31001212012120012122
4120223223020121
51322002231131
6105031351025
713155544403
oct3053531031
91055176178
10414102041
111a2827aa1
12b6822475
1367a3b2c2
143cdd5b73
152654bd7b
hex18aeb219

414102041 has 2 divisors, whose sum is σ = 414102042. Its totient is φ = 414102040.

The previous prime is 414102019. The next prime is 414102053. The reversal of 414102041 is 140201414.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 407232400 + 6869641 = 20180^2 + 2621^2 .

It is a cyclic number.

It is not a de Polignac number, because 414102041 - 222 = 409907737 is a prime.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (414102071) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 207051020 + 207051021.

It is an arithmetic number, because the mean of its divisors is an integer number (207051021).

Almost surely, 2414102041 is an apocalyptic number.

It is an amenable number.

414102041 is a deficient number, since it is larger than the sum of its proper divisors (1).

414102041 is an equidigital number, since it uses as much as digits as its factorization.

414102041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 128, while the sum is 17.

The square root of 414102041 is about 20349.4973156587. The cubic root of 414102041 is about 745.3652194857.

Adding to 414102041 its reverse (140201414), we get a palindrome (554303455).

The spelling of 414102041 in words is "four hundred fourteen million, one hundred two thousand, forty-one".