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414112201354219 is a prime number
BaseRepresentation
bin101111000101000100000001…
…0101010001010101111101011
32000022020201222022211102120011
41132022020002222022233223
5413234303242021313334
64024424304034312351
7153140422252142614
oct13612100252125753
92008221868742504
10414112201354219
1110aa48aa88663a5
123a5418764286b7
1314a0b7c7a85754
1474391cd3aac0b
1532d201e50c564
hex178a202a8abeb

414112201354219 has 2 divisors, whose sum is σ = 414112201354220. Its totient is φ = 414112201354218.

The previous prime is 414112201354213. The next prime is 414112201354277. The reversal of 414112201354219 is 912453102211414.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 414112201354219 - 221 = 414112199257067 is a prime.

It is a super-3 number, since 3×4141122013542193 (a number of 45 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (414112201354213) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 207056100677109 + 207056100677110.

It is an arithmetic number, because the mean of its divisors is an integer number (207056100677110).

Almost surely, 2414112201354219 is an apocalyptic number.

414112201354219 is a deficient number, since it is larger than the sum of its proper divisors (1).

414112201354219 is an equidigital number, since it uses as much as digits as its factorization.

414112201354219 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 69120, while the sum is 40.

The spelling of 414112201354219 in words is "four hundred fourteen trillion, one hundred twelve billion, two hundred one million, three hundred fifty-four thousand, two hundred nineteen".