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4141211104171 is a prime number
BaseRepresentation
bin111100010000110011011…
…010101011001110101011
3112122220012010022001021101
4330100303122223032223
51020322200020313141
612450240210022231
7605123033406301
oct74206332531653
915586163261241
104141211104171
111357306786249
1256a717277977
1324068c56c1cb
1410461574c271
1572ac81ac531
hex3c4336ab3ab

4141211104171 has 2 divisors, whose sum is σ = 4141211104172. Its totient is φ = 4141211104170.

The previous prime is 4141211104141. The next prime is 4141211104229. The reversal of 4141211104171 is 1714011121414.

4141211104171 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 4141211104171 - 229 = 4140674233259 is a prime.

It is a super-3 number, since 3×41412111041713 (a number of 39 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (4141211104141) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2070605552085 + 2070605552086.

It is an arithmetic number, because the mean of its divisors is an integer number (2070605552086).

Almost surely, 24141211104171 is an apocalyptic number.

4141211104171 is a deficient number, since it is larger than the sum of its proper divisors (1).

4141211104171 is an equidigital number, since it uses as much as digits as its factorization.

4141211104171 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 896, while the sum is 28.

Adding to 4141211104171 its reverse (1714011121414), we get a palindrome (5855222225585).

The spelling of 4141211104171 in words is "four trillion, one hundred forty-one billion, two hundred eleven million, one hundred four thousand, one hundred seventy-one".