Base | Representation |
---|---|
bin | 1100000011011001101… |
… | …11010110101000000101 |
3 | 1110120222100200222101202 |
4 | 12001230313112220011 |
5 | 23241131141412331 |
6 | 514131012232245 |
7 | 41630600024645 |
oct | 6015467265005 |
9 | 1416870628352 |
10 | 414143310341 |
11 | 14a701113832 |
12 | 6831b90b685 |
13 | 30090846227 |
14 | 1608a702525 |
15 | ab8d3d8ecb |
hex | 606cdd6a05 |
414143310341 has 4 divisors (see below), whose sum is σ = 419976314784. Its totient is φ = 408310305900.
The previous prime is 414143310337. The next prime is 414143310457. The reversal of 414143310341 is 143013341414.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 414143310341 - 22 = 414143310337 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (414143310331) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2916502115 + ... + 2916502256.
It is an arithmetic number, because the mean of its divisors is an integer number (104994078696).
Almost surely, 2414143310341 is an apocalyptic number.
It is an amenable number.
414143310341 is a deficient number, since it is larger than the sum of its proper divisors (5833004443).
414143310341 is an equidigital number, since it uses as much as digits as its factorization.
414143310341 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5833004442.
The product of its (nonzero) digits is 6912, while the sum is 29.
Adding to 414143310341 its reverse (143013341414), we get a palindrome (557156651755).
The spelling of 414143310341 in words is "four hundred fourteen billion, one hundred forty-three million, three hundred ten thousand, three hundred forty-one".
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