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41420521211035 = 58284104242207
BaseRepresentation
bin10010110101011111101110…
…11101000000010010011011
312102122202121100012100011111
421122233313131000102123
520412113211412223120
6224032154051441151
711503351062106261
oct1132576735002233
9172582540170144
1041420521211035
111221a3874359aa
12478b6a88b61b7
131a15c27849a55
14a32a9a2c4431
154bc69975075a
hex25abf774049b

41420521211035 has 4 divisors (see below), whose sum is σ = 49704625453248. Its totient is φ = 33136416968824.

The previous prime is 41420521211011. The next prime is 41420521211039. The reversal of 41420521211035 is 53011212502414.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 41420521211035 - 237 = 41283082257563 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 41420521210988 and 41420521211006.

It is not an unprimeable number, because it can be changed into a prime (41420521211039) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4142052121099 + ... + 4142052121108.

It is an arithmetic number, because the mean of its divisors is an integer number (12426156363312).

Almost surely, 241420521211035 is an apocalyptic number.

41420521211035 is a deficient number, since it is larger than the sum of its proper divisors (8284104242213).

41420521211035 is an equidigital number, since it uses as much as digits as its factorization.

41420521211035 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8284104242212.

The product of its (nonzero) digits is 9600, while the sum is 31.

Adding to 41420521211035 its reverse (53011212502414), we get a palindrome (94431733713449).

The spelling of 41420521211035 in words is "forty-one trillion, four hundred twenty billion, five hundred twenty-one million, two hundred eleven thousand, thirty-five".

Divisors: 1 5 8284104242207 41420521211035