Base | Representation |
---|---|
bin | 111100010001101011000… |
… | …010111101101011110001 |
3 | 112122222121011111000110212 |
4 | 330101223002331223301 |
5 | 1020331102432144101 |
6 | 12450512550033505 |
7 | 605155125402452 |
oct | 74215302755361 |
9 | 15588534430425 |
10 | 4142144412401 |
11 | 1357745598566 |
12 | 56a937948895 |
13 | 2407aaa285b8 |
14 | 1046a3699129 |
15 | 72b300b81bb |
hex | 3c46b0bdaf1 |
4142144412401 has 2 divisors, whose sum is σ = 4142144412402. Its totient is φ = 4142144412400.
The previous prime is 4142144412397. The next prime is 4142144412443. The reversal of 4142144412401 is 1042144412414.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 3362015616400 + 780128796001 = 1833580^2 + 883249^2 .
It is a cyclic number.
It is not a de Polignac number, because 4142144412401 - 22 = 4142144412397 is a prime.
It is not a weakly prime, because it can be changed into another prime (4142144412491) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2071072206200 + 2071072206201.
It is an arithmetic number, because the mean of its divisors is an integer number (2071072206201).
Almost surely, 24142144412401 is an apocalyptic number.
It is an amenable number.
4142144412401 is a deficient number, since it is larger than the sum of its proper divisors (1).
4142144412401 is an equidigital number, since it uses as much as digits as its factorization.
4142144412401 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 16384, while the sum is 32.
Adding to 4142144412401 its reverse (1042144412414), we get a palindrome (5184288824815).
The spelling of 4142144412401 in words is "four trillion, one hundred forty-two billion, one hundred forty-four million, four hundred twelve thousand, four hundred one".
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