Base | Representation |
---|---|
bin | 100110100101011111… |
… | …101100010000010011 |
3 | 10221221102012202221012 |
4 | 212211133230100103 |
5 | 1134322400112120 |
6 | 31011103321135 |
7 | 2664463564043 |
oct | 464537542023 |
9 | 127842182835 |
10 | 41431254035 |
11 | 16630954416 |
12 | 80432b01ab |
13 | 3ba3754a42 |
14 | 20106d7723 |
15 | 11274a21c5 |
hex | 9a57ec413 |
41431254035 has 4 divisors (see below), whose sum is σ = 49717504848. Its totient is φ = 33145003224.
The previous prime is 41431253959. The next prime is 41431254043. The reversal of 41431254035 is 53045213414.
41431254035 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 41431254035 - 230 = 40357512211 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 41431253992 and 41431254010.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4143125399 + ... + 4143125408.
It is an arithmetic number, because the mean of its divisors is an integer number (12429376212).
Almost surely, 241431254035 is an apocalyptic number.
41431254035 is a deficient number, since it is larger than the sum of its proper divisors (8286250813).
41431254035 is an equidigital number, since it uses as much as digits as its factorization.
41431254035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 8286250812.
The product of its (nonzero) digits is 28800, while the sum is 32.
Adding to 41431254035 its reverse (53045213414), we get a palindrome (94476467449).
The spelling of 41431254035 in words is "forty-one billion, four hundred thirty-one million, two hundred fifty-four thousand, thirty-five".
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