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4143431004241 is a prime number
BaseRepresentation
bin111100010010110111101…
…110111011000001010001
3112200002220211102122200111
4330102313232323001101
51020341221314113431
612451244350121321
7605232040300204
oct74226756730121
915602824378614
104143431004241
111358245868001
1256b0367b0241
1324095444a649
141047864c993b
1572ba800a7b1
hex3c4b7bbb051

4143431004241 has 2 divisors, whose sum is σ = 4143431004242. Its totient is φ = 4143431004240.

The previous prime is 4143431004233. The next prime is 4143431004283. The reversal of 4143431004241 is 1424001343414.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 3236167134225 + 907263870016 = 1798935^2 + 952504^2 .

It is a cyclic number.

It is not a de Polignac number, because 4143431004241 - 23 = 4143431004233 is a prime.

It is a super-4 number, since 4×41434310042414 (a number of 52 digits) contains 4444 as substring.

It is not a weakly prime, because it can be changed into another prime (4143431002241) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2071715502120 + 2071715502121.

It is an arithmetic number, because the mean of its divisors is an integer number (2071715502121).

Almost surely, 24143431004241 is an apocalyptic number.

It is an amenable number.

4143431004241 is a deficient number, since it is larger than the sum of its proper divisors (1).

4143431004241 is an equidigital number, since it uses as much as digits as its factorization.

4143431004241 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 18432, while the sum is 31.

Adding to 4143431004241 its reverse (1424001343414), we get a palindrome (5567432347655).

The spelling of 4143431004241 in words is "four trillion, one hundred forty-three billion, four hundred thirty-one million, four thousand, two hundred forty-one".