Base | Representation |
---|---|
bin | 1100000011111000101… |
… | …10011010110111111011 |
3 | 1110121122110120021212211 |
4 | 12001330112122313323 |
5 | 23242144144044233 |
6 | 514212452515551 |
7 | 41640203223325 |
oct | 6017426326773 |
9 | 1417573507784 |
10 | 414403112443 |
11 | 14a824831a11 |
12 | 6839291bbb7 |
13 | 3010260b398 |
14 | 160b3010615 |
15 | aba61075cd |
hex | 607c59adfb |
414403112443 has 4 divisors (see below), whose sum is σ = 414457711408. Its totient is φ = 414348513480.
The previous prime is 414403112437. The next prime is 414403112531. The reversal of 414403112443 is 344211304414.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 344211304414 = 2 ⋅172105652207.
It is a cyclic number.
It is not a de Polignac number, because 414403112443 - 229 = 413866241531 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (414403112243) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 27288096 + ... + 27303277.
It is an arithmetic number, because the mean of its divisors is an integer number (103614427852).
Almost surely, 2414403112443 is an apocalyptic number.
414403112443 is a deficient number, since it is larger than the sum of its proper divisors (54598965).
414403112443 is an equidigital number, since it uses as much as digits as its factorization.
414403112443 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 54598964.
The product of its (nonzero) digits is 18432, while the sum is 31.
Adding to 414403112443 its reverse (344211304414), we get a palindrome (758614416857).
The spelling of 414403112443 in words is "four hundred fourteen billion, four hundred three million, one hundred twelve thousand, four hundred forty-three".
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