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4144113403013 = 33231247100031
BaseRepresentation
bin111100010011100000011…
…010000100010010000101
3112200011200101111002211002
4330103200122010102011
51020344121012344023
612451440204223045
7605254664503043
oct74234032042205
915604611432732
104144113403013
111358565a85331
1256b1a723aa85
13240a329363bc
1410480cda1393
1572be7da2b28
hex3c4e0684485

4144113403013 has 4 divisors (see below), whose sum is σ = 4145360506368. Its totient is φ = 4142866299660.

The previous prime is 4144113402967. The next prime is 4144113403049. The reversal of 4144113403013 is 3103043114414.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 4144113403013 - 222 = 4144109208709 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (4144113403093) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 623546693 + ... + 623553338.

It is an arithmetic number, because the mean of its divisors is an integer number (1036340126592).

Almost surely, 24144113403013 is an apocalyptic number.

It is an amenable number.

4144113403013 is a deficient number, since it is larger than the sum of its proper divisors (1247103355).

4144113403013 is a wasteful number, since it uses less digits than its factorization.

4144113403013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1247103354.

The product of its (nonzero) digits is 6912, while the sum is 29.

Adding to 4144113403013 its reverse (3103043114414), we get a palindrome (7247156517427).

The spelling of 4144113403013 in words is "four trillion, one hundred forty-four billion, one hundred thirteen million, four hundred three thousand, thirteen".

Divisors: 1 3323 1247100031 4144113403013