Base | Representation |
---|---|
bin | 10010110110001011110000… |
… | …00010000011000111110111 |
3 | 12102202000121022000220101102 |
4 | 21123011320002003013313 |
5 | 20413010111212221403 |
6 | 224051103044120315 |
7 | 11505145516053113 |
oct | 1133057002030767 |
9 | 172660538026342 |
10 | 41444153242103 |
11 | 12229404070697 |
12 | 47941a309609b |
13 | 1a1822283b0a1 |
14 | a33c9cad6743 |
15 | 4bd0ce2a8b88 |
hex | 25b1780831f7 |
41444153242103 has 2 divisors, whose sum is σ = 41444153242104. Its totient is φ = 41444153242102.
The previous prime is 41444153242099. The next prime is 41444153242109. The reversal of 41444153242103 is 30124235144414.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 41444153242103 - 22 = 41444153242099 is a prime.
It is a super-2 number, since 2×414441532421032 (a number of 28 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (41444153242109) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20722076621051 + 20722076621052.
It is an arithmetic number, because the mean of its divisors is an integer number (20722076621052).
Almost surely, 241444153242103 is an apocalyptic number.
41444153242103 is a deficient number, since it is larger than the sum of its proper divisors (1).
41444153242103 is an equidigital number, since it uses as much as digits as its factorization.
41444153242103 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 184320, while the sum is 38.
Adding to 41444153242103 its reverse (30124235144414), we get a palindrome (71568388386517).
The spelling of 41444153242103 in words is "forty-one trillion, four hundred forty-four billion, one hundred fifty-three million, two hundred forty-two thousand, one hundred three".
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