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414545202545407 is a prime number
BaseRepresentation
bin101111001000001101101001…
…1100010101000001011111111
32000100210010121220222000021021
41132100123103202220023333
5413313402033322423112
64025355234220445011
7153213621365426203
oct13620332342501377
92010703556860237
10414545202545407
111100a56a673611a
123a5b17796a9767
1314a405a249964b
147452148410b03
1532dd41325b907
hex17906d38a82ff

414545202545407 has 2 divisors, whose sum is σ = 414545202545408. Its totient is φ = 414545202545406.

The previous prime is 414545202545371. The next prime is 414545202545413. The reversal of 414545202545407 is 704545202545414.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-414545202545407 is a prime.

It is a super-3 number, since 3×4145452025454073 (a number of 45 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (414545202545207) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 207272601272703 + 207272601272704.

It is an arithmetic number, because the mean of its divisors is an integer number (207272601272704).

Almost surely, 2414545202545407 is an apocalyptic number.

414545202545407 is a deficient number, since it is larger than the sum of its proper divisors (1).

414545202545407 is an equidigital number, since it uses as much as digits as its factorization.

414545202545407 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 17920000, while the sum is 52.

The spelling of 414545202545407 in words is "four hundred fourteen trillion, five hundred forty-five billion, two hundred two million, five hundred forty-five thousand, four hundred seven".