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41491104241 is a prime number
BaseRepresentation
bin100110101001000100…
…000000000111110001
310222002120211110222111
4212221010000013301
51134433210313431
631021042205321
72666121365326
oct465104000761
9128076743874
1041491104241
11166617127a4
12805b353841
133bb2c7b772
142018636b4d
15112c8757b1
hex9a91001f1

41491104241 has 2 divisors, whose sum is σ = 41491104242. Its totient is φ = 41491104240.

The previous prime is 41491104209. The next prime is 41491104253. The reversal of 41491104241 is 14240119414.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 25598720016 + 15892384225 = 159996^2 + 126065^2 .

It is a cyclic number.

It is not a de Polignac number, because 41491104241 - 25 = 41491104209 is a prime.

It is a super-2 number, since 2×414911042412 (a number of 22 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (41491107241) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20745552120 + 20745552121.

It is an arithmetic number, because the mean of its divisors is an integer number (20745552121).

Almost surely, 241491104241 is an apocalyptic number.

It is an amenable number.

41491104241 is a deficient number, since it is larger than the sum of its proper divisors (1).

41491104241 is an equidigital number, since it uses as much as digits as its factorization.

41491104241 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4608, while the sum is 31.

The spelling of 41491104241 in words is "forty-one billion, four hundred ninety-one million, one hundred four thousand, two hundred forty-one".