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415151441113 is a prime number
BaseRepresentation
bin1100000101010001111…
…01000100010011011001
31110200120121200022211111
412002220331010103121
523300212232103423
6514415024100321
741664561011503
oct6025075042331
91420517608744
10415151441113
11150079190362
12685614646a1
13301c166c206
1416144568d73
15abebb7460d
hex60a8f444d9

415151441113 has 2 divisors, whose sum is σ = 415151441114. Its totient is φ = 415151441112.

The previous prime is 415151441099. The next prime is 415151441123. The reversal of 415151441113 is 311144151514.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 268850546064 + 146300895049 = 518508^2 + 382493^2 .

It is a cyclic number.

It is not a de Polignac number, because 415151441113 - 29 = 415151440601 is a prime.

It is not a weakly prime, because it can be changed into another prime (415151441123) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 207575720556 + 207575720557.

It is an arithmetic number, because the mean of its divisors is an integer number (207575720557).

Almost surely, 2415151441113 is an apocalyptic number.

It is an amenable number.

415151441113 is a deficient number, since it is larger than the sum of its proper divisors (1).

415151441113 is an equidigital number, since it uses as much as digits as its factorization.

415151441113 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 4800, while the sum is 31.

Adding to 415151441113 its reverse (311144151514), we get a palindrome (726295592627).

The spelling of 415151441113 in words is "four hundred fifteen billion, one hundred fifty-one million, four hundred forty-one thousand, one hundred thirteen".