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415215531253 is a prime number
BaseRepresentation
bin1100000101011001100…
…01100011010011110101
31110200202002021102222101
412002230301203103311
523300330134000003
6514425233502101
741666266532305
oct6025461432365
91420662242871
10415215531253
11150101385216
126857aa11931
1330201a1ba83
141614cc8d605
15ac025d411d
hex60acc634f5

415215531253 has 2 divisors, whose sum is σ = 415215531254. Its totient is φ = 415215531252.

The previous prime is 415215531233. The next prime is 415215531259. The reversal of 415215531253 is 352135512514.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 280139435524 + 135076095729 = 529282^2 + 367527^2 .

It is a cyclic number.

It is not a de Polignac number, because 415215531253 - 225 = 415181976821 is a prime.

It is a super-2 number, since 2×4152155312532 (a number of 24 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (415215531259) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 207607765626 + 207607765627.

It is an arithmetic number, because the mean of its divisors is an integer number (207607765627).

Almost surely, 2415215531253 is an apocalyptic number.

It is an amenable number.

415215531253 is a deficient number, since it is larger than the sum of its proper divisors (1).

415215531253 is an equidigital number, since it uses as much as digits as its factorization.

415215531253 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 90000, while the sum is 37.

The spelling of 415215531253 in words is "four hundred fifteen billion, two hundred fifteen million, five hundred thirty-one thousand, two hundred fifty-three".