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41534004041 is a prime number
BaseRepresentation
bin100110101011100111…
…101001101101001001
310222012120120000102222
4212223213221231021
51140030201112131
631025213503425
73000152131535
oct465347515511
9128176500388
1041534004041
1116683953a82
1280717a1b75
133bbbb1c16a
142020202bc5
1511314eb87b
hex9ab9e9b49

41534004041 has 2 divisors, whose sum is σ = 41534004042. Its totient is φ = 41534004040.

The previous prime is 41534003993. The next prime is 41534004059. The reversal of 41534004041 is 14040043514.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 41055269641 + 478734400 = 202621^2 + 21880^2 .

It is a cyclic number.

It is not a de Polignac number, because 41534004041 - 218 = 41533741897 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 41534004041.

It is not a weakly prime, because it can be changed into another prime (41534004091) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20767002020 + 20767002021.

It is an arithmetic number, because the mean of its divisors is an integer number (20767002021).

Almost surely, 241534004041 is an apocalyptic number.

It is an amenable number.

41534004041 is a deficient number, since it is larger than the sum of its proper divisors (1).

41534004041 is an equidigital number, since it uses as much as digits as its factorization.

41534004041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3840, while the sum is 26.

Adding to 41534004041 its reverse (14040043514), we get a palindrome (55574047555).

The spelling of 41534004041 in words is "forty-one billion, five hundred thirty-four million, four thousand, forty-one".