4155013001 has 2 divisors, whose sum is σ = 4155013002. Its totient is φ = 4155013000.

The previous prime is 4155012989. The next prime is 4155013003. The reversal of 4155013001 is 1003105514.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 4153931401 + 1081600 = 64451^2 + 1040^2 .

It is a cyclic number.

It is not a de Polignac number, because 4155013001 - 2¹⁴ = 4154996617 is a prime.

Together with 4155013003, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (4155013003) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2077506500 + 2077506501.

It is an arithmetic number, because the mean of its divisors is an integer number (2077506501).

Almost surely, 2^4155013001 is an apocalyptic number.

It is an amenable number.

4155013001 is a deficient number, since it is larger than the sum of its proper divisors (1).

4155013001 is an equidigital number, since it uses as much as digits as its factorization.

4155013001 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 300, while the sum is 20.

The square root of 4155013001 is about 64459.3903244516. The cubic root of 4155013001 is about 1607.6473748079.

Adding to 4155013001 its reverse (1003105514), we get a palindrome (5158118515).

The spelling of 4155013001 in words is "four billion, one hundred fifty-five million, thirteen thousand, one".