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4155211210253 is a prime number
BaseRepresentation
bin111100011101110101111…
…000110101111000001101
3112201020022210222010100212
4330131311320311320031
51021034333032212003
612500513324532205
7606130002346145
oct74356570657015
915636283863325
104155211210253
111362240447154
125713839b1065
13241ab0bb744c
14105182c51925
1573147311dd8
hex3c775e35e0d

4155211210253 has 2 divisors, whose sum is σ = 4155211210254. Its totient is φ = 4155211210252.

The previous prime is 4155211210247. The next prime is 4155211210277. The reversal of 4155211210253 is 3520121125514.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 2567820363364 + 1587390846889 = 1602442^2 + 1259917^2 .

It is a cyclic number.

It is not a de Polignac number, because 4155211210253 - 220 = 4155210161677 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4155211210243) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2077605605126 + 2077605605127.

It is an arithmetic number, because the mean of its divisors is an integer number (2077605605127).

Almost surely, 24155211210253 is an apocalyptic number.

It is an amenable number.

4155211210253 is a deficient number, since it is larger than the sum of its proper divisors (1).

4155211210253 is an equidigital number, since it uses as much as digits as its factorization.

4155211210253 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 12000, while the sum is 32.

Adding to 4155211210253 its reverse (3520121125514), we get a palindrome (7675332335767).

The spelling of 4155211210253 in words is "four trillion, one hundred fifty-five billion, two hundred eleven million, two hundred ten thousand, two hundred fifty-three".