Base | Representation |
---|---|
bin | 111100011101110101111… |
… | …000110101111000001101 |
3 | 112201020022210222010100212 |
4 | 330131311320311320031 |
5 | 1021034333032212003 |
6 | 12500513324532205 |
7 | 606130002346145 |
oct | 74356570657015 |
9 | 15636283863325 |
10 | 4155211210253 |
11 | 1362240447154 |
12 | 5713839b1065 |
13 | 241ab0bb744c |
14 | 105182c51925 |
15 | 73147311dd8 |
hex | 3c775e35e0d |
4155211210253 has 2 divisors, whose sum is σ = 4155211210254. Its totient is φ = 4155211210252.
The previous prime is 4155211210247. The next prime is 4155211210277. The reversal of 4155211210253 is 3520121125514.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 2567820363364 + 1587390846889 = 1602442^2 + 1259917^2 .
It is a cyclic number.
It is not a de Polignac number, because 4155211210253 - 220 = 4155210161677 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4155211210243) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2077605605126 + 2077605605127.
It is an arithmetic number, because the mean of its divisors is an integer number (2077605605127).
Almost surely, 24155211210253 is an apocalyptic number.
It is an amenable number.
4155211210253 is a deficient number, since it is larger than the sum of its proper divisors (1).
4155211210253 is an equidigital number, since it uses as much as digits as its factorization.
4155211210253 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 12000, while the sum is 32.
Adding to 4155211210253 its reverse (3520121125514), we get a palindrome (7675332335767).
The spelling of 4155211210253 in words is "four trillion, one hundred fifty-five billion, two hundred eleven million, two hundred ten thousand, two hundred fifty-three".
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