Base | Representation |
---|---|
bin | 11000110001001… |
… | …000000010000101 |
3 | 1001221220011120021 |
4 | 120301020002011 |
5 | 1322333444031 |
6 | 105122135141 |
7 | 13203646024 |
oct | 3061100205 |
9 | 1057804507 |
10 | 415531141 |
11 | 1a3613773 |
12 | b71b14b1 |
13 | 6811b91c |
14 | 3d2888bb |
15 | 26730511 |
hex | 18c48085 |
415531141 has 2 divisors, whose sum is σ = 415531142. Its totient is φ = 415531140.
The previous prime is 415531097. The next prime is 415531157. The reversal of 415531141 is 141135514.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 253478241 + 162052900 = 15921^2 + 12730^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-415531141 is a prime.
It is a super-2 number, since 2×4155311412 = 345332258281523762, which contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (415537141) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 207765570 + 207765571.
It is an arithmetic number, because the mean of its divisors is an integer number (207765571).
Almost surely, 2415531141 is an apocalyptic number.
It is an amenable number.
415531141 is a deficient number, since it is larger than the sum of its proper divisors (1).
415531141 is an equidigital number, since it uses as much as digits as its factorization.
415531141 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 1200, while the sum is 25.
The square root of 415531141 is about 20384.5809620899. The cubic root of 415531141 is about 746.2216737796.
Adding to 415531141 its reverse (141135514), we get a palindrome (556666655).
The spelling of 415531141 in words is "four hundred fifteen million, five hundred thirty-one thousand, one hundred forty-one".
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