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41613656782001 is a prime number
BaseRepresentation
bin10010111011000111011110…
…01110101111010010110001
312110100020010021211220021112
421131203233032233102301
520423244232114011001
6224301014445203105
711523326131266533
oct1135435716572261
9173306107756245
1041613656782001
1112294286429a57
124801009560495
131a2b1c697c3a5
14a3c17c859853
154c2700239cbb
hex25d8ef3af4b1

41613656782001 has 2 divisors, whose sum is σ = 41613656782002. Its totient is φ = 41613656782000.

The previous prime is 41613656781847. The next prime is 41613656782003. The reversal of 41613656782001 is 10028765631614.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 27882370701376 + 13731286080625 = 5280376^2 + 3705575^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-41613656782001 is a prime.

Together with 41613656782003, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (41613656782003) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20806828391000 + 20806828391001.

It is an arithmetic number, because the mean of its divisors is an integer number (20806828391001).

Almost surely, 241613656782001 is an apocalyptic number.

It is an amenable number.

41613656782001 is a deficient number, since it is larger than the sum of its proper divisors (1).

41613656782001 is an equidigital number, since it uses as much as digits as its factorization.

41613656782001 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1451520, while the sum is 50.

The spelling of 41613656782001 in words is "forty-one trillion, six hundred thirteen billion, six hundred fifty-six million, seven hundred eighty-two thousand, one".