Base | Representation |
---|---|
bin | 111100100110010000101… |
… | …101110100011110011111 |
3 | 112202002122211101020100102 |
4 | 330212100231310132133 |
5 | 1021211341304142401 |
6 | 12505010340051315 |
7 | 606600012342056 |
oct | 74462055643637 |
9 | 15662584336312 |
10 | 4164251240351 |
11 | 136605a299604 |
12 | 573087393b3b |
13 | 2428c1a41b97 |
14 | 10579d6c739d |
15 | 734c5c9956b |
hex | 3c990b7479f |
4164251240351 has 2 divisors, whose sum is σ = 4164251240352. Its totient is φ = 4164251240350.
The previous prime is 4164251240311. The next prime is 4164251240371. The reversal of 4164251240351 is 1530421524614.
4164251240351 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-4164251240351 is a prime.
It is a Sophie Germain prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4164251240311) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2082125620175 + 2082125620176.
It is an arithmetic number, because the mean of its divisors is an integer number (2082125620176).
Almost surely, 24164251240351 is an apocalyptic number.
4164251240351 is a deficient number, since it is larger than the sum of its proper divisors (1).
4164251240351 is an equidigital number, since it uses as much as digits as its factorization.
4164251240351 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 115200, while the sum is 38.
Adding to 4164251240351 its reverse (1530421524614), we get a palindrome (5694672764965).
The spelling of 4164251240351 in words is "four trillion, one hundred sixty-four billion, two hundred fifty-one million, two hundred forty thousand, three hundred fifty-one".
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