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42000411313303 = 94723443402461
BaseRepresentation
bin10011000110010111110111…
…00110001100010010010111
312111201012101212201202001121
421203023323212030102113
521001113320244011203
6225154420025104411
711563300226462662
oct1143137346142227
9174635355652047
1042000411313303
1112423302268703
124863b64928107
131a58811101991
14a52b8b8366d9
154cc7d8d950bd
hex2632fb98c497

42000411313303 has 4 divisors (see below), whose sum is σ = 42000854810488. Its totient is φ = 41999967816120.

The previous prime is 42000411313297. The next prime is 42000411313379. The reversal of 42000411313303 is 30331311400024.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 42000411313303 - 217 = 42000411182231 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (42000411713303) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 221606508 + ... + 221795953.

It is an arithmetic number, because the mean of its divisors is an integer number (10500213702622).

Almost surely, 242000411313303 is an apocalyptic number.

42000411313303 is a deficient number, since it is larger than the sum of its proper divisors (443497185).

42000411313303 is an equidigital number, since it uses as much as digits as its factorization.

42000411313303 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 443497184.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 42000411313303 its reverse (30331311400024), we get a palindrome (72331722713327).

The spelling of 42000411313303 in words is "forty-two trillion, four hundred eleven million, three hundred thirteen thousand, three hundred three".

Divisors: 1 94723 443402461 42000411313303