42004341201233 has 2 divisors, whose sum is σ = 42004341201234. Its totient is φ = 42004341201232.

The previous prime is 42004341201167. The next prime is 42004341201257. The reversal of 42004341201233 is 33210214340024.

42004341201233 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 36463929100369 + 5540412100864 = 6038537^2 + 2353808^2 .

It is a cyclic number.

It is not a de Polignac number, because 42004341201233 - 2²⁰ = 42004340152657 is a prime.

It is a super-3 number, since 3×42004341201233³ (a number of 42 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 42004341201196 and 42004341201205.

It is not a weakly prime, because it can be changed into another prime (42004341203233) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21002170600616 + 21002170600617.

It is an arithmetic number, because the mean of its divisors is an integer number (21002170600617).

Almost surely, 2^{42004341201233} is an apocalyptic number.

It is an amenable number.

42004341201233 is a deficient number, since it is larger than the sum of its proper divisors (1).

42004341201233 is an equidigital number, since it uses as much as digits as its factorization.

42004341201233 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 13824, while the sum is 29.

Adding to 42004341201233 its reverse (33210214340024), we get a palindrome (75214555541257).

The spelling of 42004341201233 in words is "forty-two trillion, four billion, three hundred forty-one million, two hundred one thousand, two hundred thirty-three".