Base | Representation |
---|---|
bin | 101111110000110011111111… |
… | …1111100011011001110111111 |
3 | 2001002112120100021022022011221 |
4 | 1133201213333330123032333 |
5 | 420031312211131214403 |
6 | 4045310451111054211 |
7 | 154331015606423212 |
oct | 13741477774331677 |
9 | 2032476307268157 |
10 | 420125110023103 |
11 | 111957070a72841 |
12 | 3b153089371367 |
13 | 150568215ba454 |
14 | 75a624174d779 |
15 | 33886418a5dbd |
hex | 17e19fff1b3bf |
420125110023103 has 2 divisors, whose sum is σ = 420125110023104. Its totient is φ = 420125110023102.
The previous prime is 420125110023089. The next prime is 420125110023109. The reversal of 420125110023103 is 301320011521024.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 420125110023103 - 217 = 420125109892031 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (420125110023109) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 210062555011551 + 210062555011552.
It is an arithmetic number, because the mean of its divisors is an integer number (210062555011552).
Almost surely, 2420125110023103 is an apocalyptic number.
420125110023103 is a deficient number, since it is larger than the sum of its proper divisors (1).
420125110023103 is an equidigital number, since it uses as much as digits as its factorization.
420125110023103 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1440, while the sum is 25.
Adding to 420125110023103 its reverse (301320011521024), we get a palindrome (721445121544127).
The spelling of 420125110023103 in words is "four hundred twenty trillion, one hundred twenty-five billion, one hundred ten million, twenty-three thousand, one hundred three".
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