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42014440233341 is a prime number
BaseRepresentation
bin10011000110110001111111…
…10010010001100101111101
312111202112121120121201110122
421203120333302101211331
521001331033144431331
6225205100053344325
711564304665361332
oct1143307762214575
9174675546551418
1042014440233341
11124292512199a4
12486681b0380a5
131a59c386c80b4
14a5371caba989
154ccd5a7dc17b
hex26363fc9197d

42014440233341 has 2 divisors, whose sum is σ = 42014440233342. Its totient is φ = 42014440233340.

The previous prime is 42014440233331. The next prime is 42014440233427. The reversal of 42014440233341 is 14333204441024.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 29183386687225 + 12831053546116 = 5402165^2 + 3582046^2 .

It is a cyclic number.

It is not a de Polignac number, because 42014440233341 - 218 = 42014439971197 is a prime.

It is a super-3 number, since 3×420144402333413 (a number of 42 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (42014440233331) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21007220116670 + 21007220116671.

It is an arithmetic number, because the mean of its divisors is an integer number (21007220116671).

Almost surely, 242014440233341 is an apocalyptic number.

It is an amenable number.

42014440233341 is a deficient number, since it is larger than the sum of its proper divisors (1).

42014440233341 is an equidigital number, since it uses as much as digits as its factorization.

42014440233341 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 110592, while the sum is 35.

Adding to 42014440233341 its reverse (14333204441024), we get a palindrome (56347644674365).

The spelling of 42014440233341 in words is "forty-two trillion, fourteen billion, four hundred forty million, two hundred thirty-three thousand, three hundred forty-one".