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42021405004013 is a prime number
BaseRepresentation
bin10011000110111110111101…
…11010110001000011101101
312111210012120222001201200222
421203133132322301003231
521001434314140112023
6225212211132501125
711564642406062231
oct1143373672610355
9174705528051628
1042021405004013
11124311a56a1216
12486804361a7a5
131a5a7a8617a86
14a53bbdaa65c1
154cd116e97cc8
hex2637deeb10ed

42021405004013 has 2 divisors, whose sum is σ = 42021405004014. Its totient is φ = 42021405004012.

The previous prime is 42021405003973. The next prime is 42021405004021. The reversal of 42021405004013 is 31040050412024.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 25397951171044 + 16623453832969 = 5039638^2 + 4077187^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-42021405004013 is a prime.

It is a super-2 number, since 2×420214050040132 (a number of 28 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (42021405004063) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21010702502006 + 21010702502007.

It is an arithmetic number, because the mean of its divisors is an integer number (21010702502007).

Almost surely, 242021405004013 is an apocalyptic number.

It is an amenable number.

42021405004013 is a deficient number, since it is larger than the sum of its proper divisors (1).

42021405004013 is an equidigital number, since it uses as much as digits as its factorization.

42021405004013 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3840, while the sum is 26.

Adding to 42021405004013 its reverse (31040050412024), we get a palindrome (73061455416037).

The spelling of 42021405004013 in words is "forty-two trillion, twenty-one billion, four hundred five million, four thousand, thirteen".