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421001300011 is a prime number
BaseRepresentation
bin1100010000001011010…
…00100000100000101011
31111020200022012221122011
412020011220200200223
523344202313100021
6521223314540351
742262543001635
oct6100550404053
91436608187564
10421001300011
11152600292996
12697145976b7
13309145b9a96
141653b453a55
15ae40500de1
hex6205a2082b

421001300011 has 2 divisors, whose sum is σ = 421001300012. Its totient is φ = 421001300010.

The previous prime is 421001299951. The next prime is 421001300017. The reversal of 421001300011 is 110003100124.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 421001300011 - 211 = 421001297963 is a prime.

It is a super-2 number, since 2×4210013000112 (a number of 24 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 421001299964 and 421001300000.

It is not a weakly prime, because it can be changed into another prime (421001300017) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 210500650005 + 210500650006.

It is an arithmetic number, because the mean of its divisors is an integer number (210500650006).

Almost surely, 2421001300011 is an apocalyptic number.

421001300011 is a deficient number, since it is larger than the sum of its proper divisors (1).

421001300011 is an equidigital number, since it uses as much as digits as its factorization.

421001300011 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 24, while the sum is 13.

Adding to 421001300011 its reverse (110003100124), we get a palindrome (531004400135).

The spelling of 421001300011 in words is "four hundred twenty-one billion, one million, three hundred thousand, eleven".