4211313112841 has 2 divisors, whose sum is σ = 4211313112842. Its totient is φ = 4211313112840.

The previous prime is 4211313112819. The next prime is 4211313112843. The reversal of 4211313112841 is 1482113131124.

4211313112841 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 4083749847241 + 127563265600 = 2020829^2 + 357160^2 .

It is a cyclic number.

It is not a de Polignac number, because 4211313112841 - 2¹⁸ = 4211312850697 is a prime.

Together with 4211313112843, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 4211313112798 and 4211313112807.

It is not a weakly prime, because it can be changed into another prime (4211313112843) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2105656556420 + 2105656556421.

It is an arithmetic number, because the mean of its divisors is an integer number (2105656556421).

Almost surely, 2^{4211313112841} is an apocalyptic number.

It is an amenable number.

4211313112841 is a deficient number, since it is larger than the sum of its proper divisors (1).

4211313112841 is an equidigital number, since it uses as much as digits as its factorization.

4211313112841 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 4608, while the sum is 32.

Adding to 4211313112841 its reverse (1482113131124), we get a palindrome (5693426243965).

The spelling of 4211313112841 in words is "four trillion, two hundred eleven billion, three hundred thirteen million, one hundred twelve thousand, eight hundred forty-one".