Base | Representation |
---|---|
bin | 10011001001111000101110… |
… | …01010101000100011101011 |
3 | 12112010202000011202112222111 |
4 | 21210330113022220203223 |
5 | 21010103040012413103 |
6 | 225330103100303151 |
7 | 11605102640362624 |
oct | 1144742712504353 |
9 | 175122004675874 |
10 | 42121132935403 |
11 | 1246a5214a0125 |
12 | 4883436241ab7 |
13 | 1a6700c958c72 |
14 | a58960944a4b |
15 | 4d0a0238e86d |
hex | 264f172a88eb |
42121132935403 has 2 divisors, whose sum is σ = 42121132935404. Its totient is φ = 42121132935402.
The previous prime is 42121132935347. The next prime is 42121132935419. The reversal of 42121132935403 is 30453923112124.
42121132935403 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 42121132935403 - 233 = 42112543000811 is a prime.
It is not a weakly prime, because it can be changed into another prime (42121132945403) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21060566467701 + 21060566467702.
It is an arithmetic number, because the mean of its divisors is an integer number (21060566467702).
Almost surely, 242121132935403 is an apocalyptic number.
42121132935403 is a deficient number, since it is larger than the sum of its proper divisors (1).
42121132935403 is an equidigital number, since it uses as much as digits as its factorization.
42121132935403 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 155520, while the sum is 40.
The spelling of 42121132935403 in words is "forty-two trillion, one hundred twenty-one billion, one hundred thirty-two million, nine hundred thirty-five thousand, four hundred three".
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