Base | Representation |
---|---|
bin | 111101010011110110100… |
… | …001110111011101010101 |
3 | 112220210000102200021000002 |
4 | 331103312201313131111 |
5 | 1023012120212220000 |
6 | 12543304052101045 |
7 | 613252060206266 |
oct | 75236641673525 |
9 | 15823012607002 |
10 | 4213204023125 |
11 | 138489a918879 |
12 | 580669604785 |
13 | 2473c3851b36 |
14 | 107cc4cd896d |
15 | 748dd7328d5 |
hex | 3d4f6877755 |
4213204023125 has 20 divisors (see below), whose sum is σ = 5265026152320. Its totient is φ = 3370431078000.
The previous prime is 4213204023113. The next prime is 4213204023139. The reversal of 4213204023125 is 5213204023124.
It is not a de Polignac number, because 4213204023125 - 24 = 4213204023109 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 19 ways as a sum of consecutive naturals, for example, 17759036 + ... + 17994714.
It is an arithmetic number, because the mean of its divisors is an integer number (263251307616).
Almost surely, 24213204023125 is an apocalyptic number.
It is an amenable number.
4213204023125 is a deficient number, since it is larger than the sum of its proper divisors (1051822129195).
4213204023125 is an equidigital number, since it uses as much as digits as its factorization.
4213204023125 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 264302 (or 264287 counting only the distinct ones).
The product of its (nonzero) digits is 11520, while the sum is 29.
Adding to 4213204023125 its reverse (5213204023124), we get a palindrome (9426408046249).
Subtracting 4213204023125 from its reverse (5213204023124), we obtain a palindrome (999999999999).
The spelling of 4213204023125 in words is "four trillion, two hundred thirteen billion, two hundred four million, twenty-three thousand, one hundred twenty-five".
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