Base | Representation |
---|---|
bin | 100111001111011010… |
… | …001001100001010001 |
3 | 11000202102101112101011 |
4 | 213033122021201101 |
5 | 1142242404202423 |
6 | 31204543210521 |
7 | 3021062602636 |
oct | 471732114121 |
9 | 130672345334 |
10 | 42134444113 |
11 | 16961882543 |
12 | 81ba8a6a41 |
13 | 3c86340148 |
14 | 2079c6218d |
15 | 11690a4b0d |
hex | 9cf689851 |
42134444113 has 2 divisors, whose sum is σ = 42134444114. Its totient is φ = 42134444112.
The previous prime is 42134444089. The next prime is 42134444141. The reversal of 42134444113 is 31144443124.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 41520990289 + 613453824 = 203767^2 + 24768^2 .
It is a cyclic number.
It is not a de Polignac number, because 42134444113 - 25 = 42134444081 is a prime.
It is a super-2 number, since 2×421344441132 (a number of 22 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (42134444153) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21067222056 + 21067222057.
It is an arithmetic number, because the mean of its divisors is an integer number (21067222057).
Almost surely, 242134444113 is an apocalyptic number.
It is an amenable number.
42134444113 is a deficient number, since it is larger than the sum of its proper divisors (1).
42134444113 is an equidigital number, since it uses as much as digits as its factorization.
42134444113 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 18432, while the sum is 31.
Adding to 42134444113 its reverse (31144443124), we get a palindrome (73278887237).
The spelling of 42134444113 in words is "forty-two billion, one hundred thirty-four million, four hundred forty-four thousand, one hundred thirteen".
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