Base | Representation |
---|---|
bin | 111101011101011111011… |
… | …100000101100000100011 |
3 | 112221202201202002002211212 |
4 | 331131133130011200203 |
5 | 1023144314314100313 |
6 | 12552135101100335 |
7 | 614066415040064 |
oct | 75353734054043 |
9 | 15852652062755 |
10 | 4223554050083 |
11 | 1389221176265 |
12 | 5826778576ab |
13 | 248382c04844 |
14 | 1085c773456b |
15 | 74ce71d23a8 |
hex | 3d75f705823 |
4223554050083 has 2 divisors, whose sum is σ = 4223554050084. Its totient is φ = 4223554050082.
The previous prime is 4223554050077. The next prime is 4223554050197. The reversal of 4223554050083 is 3800504553224.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 4223554050083 - 216 = 4223553984547 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 4223554050083.
It is not a weakly prime, because it can be changed into another prime (4223854050083) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2111777025041 + 2111777025042.
It is an arithmetic number, because the mean of its divisors is an integer number (2111777025042).
Almost surely, 24223554050083 is an apocalyptic number.
4223554050083 is a deficient number, since it is larger than the sum of its proper divisors (1).
4223554050083 is an equidigital number, since it uses as much as digits as its factorization.
4223554050083 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 576000, while the sum is 41.
The spelling of 4223554050083 in words is "four trillion, two hundred twenty-three billion, five hundred fifty-four million, fifty thousand, eighty-three".
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