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42244444020133 is a prime number
BaseRepresentation
bin10011001101011110011010…
…00101000101110110100101
312112120112021221022200211201
421212233031011011312211
521014113110132121013
6225502455113002501
711620026463325365
oct1146571505056645
9175515257280751
1042244444020133
111250784a380203
1248a330a9b3431
131a75831b06b64
14a608db9109a5
154d3d1cd873dd
hex266bcd145da5

42244444020133 has 2 divisors, whose sum is σ = 42244444020134. Its totient is φ = 42244444020132.

The previous prime is 42244444020019. The next prime is 42244444020137. The reversal of 42244444020133 is 33102044444224.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 31083379111009 + 11161064909124 = 5575247^2 + 3340818^2 .

It is a cyclic number.

It is not a de Polignac number, because 42244444020133 - 29 = 42244444019621 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 42244444020092 and 42244444020101.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (42244444020137) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21122222010066 + 21122222010067.

It is an arithmetic number, because the mean of its divisors is an integer number (21122222010067).

Almost surely, 242244444020133 is an apocalyptic number.

It is an amenable number.

42244444020133 is a deficient number, since it is larger than the sum of its proper divisors (1).

42244444020133 is an equidigital number, since it uses as much as digits as its factorization.

42244444020133 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 294912, while the sum is 37.

Adding to 42244444020133 its reverse (33102044444224), we get a palindrome (75346488464357).

The spelling of 42244444020133 in words is "forty-two trillion, two hundred forty-four billion, four hundred forty-four million, twenty thousand, one hundred thirty-three".